Electricity is the flow of electric charge that powers devices and makes things work.
Electricity carries steady weightage in Class 10th exams. Practising its MCQs and important questions is one of the fastest ways to secure marks from this chapter.
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An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
An important topic in Electricity — understand its concept and practise related questions.
Attempt these multiple-choice questions, then reveal the answer to check yourself.
To calculate the resistivity (ρ) of the material, we use the formula:
R = ρ × (L / A)
Where:
Calculate the area (A) of the wire's cross section:
A = π × (1 × 10⁻⁴)² = π × 10⁻⁸ m² ≈ 3.1416 × 10⁻⁸ m²
Rearrange the formula to solve for ρ:
ρ = R × (A / L)
Substitute the values:
ρ = 20 × (3.1416 × 10⁻⁸ / 1)
Calculate the resistivity:
ρ ≈ 20 × 3.1416 × 10⁻⁸ = 6.28 × 10⁻⁷ Ω·m
The resistance of a conductor depends on:
Alloys are commonly used in electrical heating devices (like electric heaters, toasters, and irons) because of the following reasons:
Unit of Current:The SI unit of electric current is the ampere (A).
Definition :- One ampere is the current when one coulomb of charge flows through a conductor in one second.
So, 1 ampere = 1 coulomb / 1 second
Resistance (R) = Resistivity (ρ) × (Length (L) / Area (A))
Given:-
Resistivity (ρ) = 2.8 × 10⁻⁸ ohm meter
Length (L) = 2 meters
Area (A) = 1.55 × 10⁻⁶ square meters
Substitute the values:
R = (2.8 × 10⁻⁸) × (2 / 1.55 × 10⁻⁶)
R = (5.6 × 10⁻⁸) / (1.55 × 10⁻⁶)
R ≈ 0.0361 ohms
Hence answer is 0.0361 ohms
The resistivity of alloys is generally higher than that of the pure metals from which they are made.
Why?
Example:
An electric circuit is a closed path through which electric current can flow. It usually includes a power source like a battery, wires to carry the current, and a device like a bulb or fan that uses the electricity.
If the path is complete (closed), electricity flows and the device works. If the path is broken (open), electricity cannot flow and the device does not work.
To find the number of electrons in one coulomb of charge:
Charge of one electron = 1.6 × 10⁻¹⁹ coulombs
Number of electrons = 1 ÷ (1.6 × 10⁻¹⁹)
= 6.25 × 10¹⁸ electrons
Hence 6.25 × 10¹⁸ electrons make up one coulomb of charge.
The resistance of a conductor depends on the following factors:
Metals are good conductors of electricity because they have a large number of free electrons (also called conduction electrons). These electrons are not tightly bound to atoms and can move freely through the metal. When a potential difference is applied, these free electrons flow easily, allowing electric current to pass.
Glass is a bad conductor (insulator) because its electrons are tightly bound to their atoms. It does not have free electrons available to move and carry electric current. As a result, electricity cannot flow through it easily.
In short:
Current will flow more easily through a thick wire than a thin wire of the same material when connected to the same source.
Because a thick wire has a larger area of cross-section, so it offers less resistance to the flow of current. Lower resistance means more current can flow.
A battery maintains a potential difference by using chemical reactions to move electrons from one terminal to another. This creates a positive terminal and a negative terminal, allowing current to flow through a connected conductor.
Given:
Current (I) = 1 A (Ampere)
Time (t) = 16 seconds
Charge of one electron (e) = 1.6 × 10⁻¹⁹ C (Coulombs)
Step 1: Calculate the total charge (Q) passing through the filament:
Q = I × t
Q = 1 A × 16 seconds
Q = 16 C (Coulombs)
Step 2: Calculate the number of electrons:
Number of electrons = Q / e
Number of electrons = 16 C / (1.6 × 10⁻¹⁹ C/electron)
Number of electrons = 1 × 10²⁰ electrons
Hence the number of electrons passing through the filament in 16 seconds is approximately 1 × 10²⁰ electrons.
Cell or Battery, These devices supply electrical energy and create the necessary potential difference to allow current to flow through a circuit.
If the resistance of an electrical component remains constant and the potential difference across it decreases to half of its original value, then the current flowing through it will also change.
According to Ohm’s Law:
Current (I) = Potential difference (V) ÷ Resistance (R)
Since resistance (R) is constant, if the potential difference (V) becomes half, then the new current will be:
I new = (1/2 × V) ÷ R = (1/2) × (V ÷ R) = (1/2) × I original
This means the current will become half of its original value.
Coils of electric toasters and electric irons are made of an alloy rather than a pure metal due to following reasons:
The cord of an electric heater does not glow because it is made of a material with low resistance, so it does not heat up much.
The heating element glows because it is made of a material with high resistance, which causes it to get very hot and produce light when current passes through it.
The rate at which energy is delivered by a current is called power.
Power (P) = Voltage (V) × Current (I)
So, the rate of energy delivery depends on both the voltage and the current.
The energy given to each coulomb of charge passing through a 6 V battery is calculated using the formula:
Energy = Voltage × Charge
Here, the voltage is 6 V and the charge is 1 coulomb.
Energy = 6 V × 1 C = 6 Joules
So, the energy given to each coulomb of charge is 6 joules.
Given:
Charge (Q) = 96000 coulombs
Potential difference (V) = 50 volts
Formula:
Heat generated (H) = Voltage (V) × Charge (Q)
H = 50 × 96000 = 4800000 joules
Hence the heat generated is 4800000 joules (4.8 million joules).
Given:
Resistance (R) = 20 ohms
Current (I) = 5 amperes
Time (t) = 30 seconds
Formula:
Heat developed (H) = I² × R × t
H = 5² × 20 × 30 = 25 × 20 × 30 = 15000 joules
Hence heat developed in 30 seconds = 15000 joules
To find the maximum resistance that can be made using five resistors, each of 1/5 Ω, you should connect all the resistors in series, because resistances add up in series.
The formula for total resistance in a series connection is:
R_total = R1 + R2 + R3 + R4 + R5
Since each resistor has a value of 1/5 Ω, we can calculate:
R_total = 1/5 + 1/5 + 1/5 + 1/5 + 1/5
R_total = 5 × 1/5 = 1 Ω
Hence the maximum resistance that can be made using five resistors, each of 1/5 Ω, is 1 Ω.
When we say that the potential difference between two points is 1 volt (1 V), it means that 1 joule of work is done to move 1 coulomb of charge from one point to the other.
In simple words:
1 volt = 1 joule / 1 coulomb
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