Questions Related to Python Programs

Use Python’s all() function to test if every element of the first tuple exists in the second tuple.

Example:-

tuple1 = (1, 2, 3)
tuple2 = (5, 3, 2, 1, 4)

is_subset = all(item in tuple2 for item in tuple1)

print(is_subset)  # True

Steps:--

• Tuples themselves don’t support removing duplicates directly because they are immutable.
• So, first concatenate the tuples.
• Convert the concatenated tuple into a set to remove duplicates (sets store unique items).
• Convert back to a tuple if you want the result as a tuple.

tuple1 = (1, 2, 3, 4)
tuple2 = (3, 4, 5, 6)

# Merge tuples
merged = tuple1 + tuple2

# Remove duplicates by converting to set, then back to tuple
result = tuple(set(merged))

print(result)

Since tuples are ordered collections, you can access elements by their index. The first element is at index 0. And the last element is at index -1.

Example:--

my_tuple = (10, 20, 30, 40, 50)

first_element = my_tuple[0]
last_element = my_tuple[-1]

print("First element:", first_element)
print("Last element:", last_element)

To check if two lists are equal (same elements in the same order), use the == operator.

Example :-- 

list1 = [1, 2, 3]
list2 = [1, 2, 3]

if list1 == list2:
    print("Lists are equal")
else:
    print("Lists are not equal")

Using set intersection we can get the common element b/w two list. This is the fast way to get unique common elements, but order is not preserved

list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]

common = list(set(list1) & set(list2))
print(common)  # Output: [3, 4]