Motion and Time Class 10th Important Questions with Answers Science
Updated on June 1, 2025 | By Learnzy Academy
Q1. Classify the following as motion along a straight line, circular or oscillatory motion: (i) Motion of your hands while running. (ii) Motion of a horse pulling a cart on a straight road. (iii) Motion of a child in a merry-go-round. (iv) Motion of a child on a see-saw. (v) Motion of the hammer of an electric bell. (vi) Motion of a train on a straight bridge.
(i) Motion of hands while running – Oscillatory
(ii) Horse pulling a cart on a straight road – Straight line
(iii) Child in a merry-go-round – Circular
(iv) Child on a see-saw – Oscillatory
(v) Hammer of an electric bell – Oscillatory
(vi) Train on a straight bridge – Straight line
Q2. Which of the following are not correct? (i) The basic unit of time is second. (ii) Every object moves with a constant speed. (iii) Distances between two cities are measured in kilometres. (iv) The time period of a given pendulum is constant. (v) The speed of a train is expressed in m/h.
The following statements are not correct:
(ii) Every object moves with a constant speed.
(iv) The time period of a given pendulum is constant.
(v) The speed of a train is expressed in m/h.
Q3. A simple pendulum takes 32 s to complete 20 oscillations. What is the time period of the pendulum?
Total time = 32 seconds
Number of oscillations = 20
Time period = Total time ÷ Number of oscillations
Time period = 32 ÷ 20 = 1.6 seconds
So, the time period of the pendulum is 1.6 seconds.
Q4. The distance between two stations is 240 km. A train takes 4 hours to cover this distance. Calculate the speed of the train.
To calculate the speed of the train, use the formula:
Speed = Distance ÷ Time
Given:
Distance = 240 km
Time = 4 hours
Speed = 240 ÷ 4 = 60 km/h
Hence the speed of the train is 60 km/h.
Q5. The odometer of a car reads 57321.0 km when the clock shows the time 08:30 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
Given:
Initial odometer reading = 57321.0 km
Final odometer reading = 57336.0 km
Initial time = 08:30 AM
Final time = 08:50 AM
Distance moved = 57336.0 – 57321.0 = 15.0 km
Time taken = 20 minutes
Speed in km/min = 15.0 ÷ 20 = 0.75 km/min
Speed in km/h = 0.75 × 60 = 45 km/h
Hence distance moved = 15.0 km & Speed = 0.75 km/min or 45 km/h
Q6. Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.
Given:
Time = 15 minutes = 15 × 60 = 900 seconds
Speed = 2 m/s
Distance = Speed × Time
Distance = 2 × 900 = 1800 meters
Hence the distance between Salma’s house and school is 1800 meters (or 1.8 kilometers).
Q7. A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
Given:
Speed1 = 40 km/h, Time1 = 15 minutes = 0.25 hours
Speed2 = 60 km/h, Time2 = 15 minutes = 0.25 hours
Distance1 = 40 × 0.25 = 10 km
Distance2 = 60 × 0.25 = 15 km
Total distance = 10 + 15 = 25 km
Hence the car covers 25 kilometers distance in total.