Questions Related to Science

Updated on December 1, 2025 | By Learnzy Academy

Q1. What are the various energy transformations that occur when you are riding a bicycle?

When you ride a bicycle, several energy transformations take place:

Chemical energy   --->  Mechanical energy:
The chemical energy stored in your muscles is converted into mechanical energy when you pedal.

Mechanical energy --->  Kinetic energy:
The pedaling moves the bicycle, giving it kinetic energy as it moves forward.

Mechanical energy   ---->  Heat energy:
Some energy is lost as heat due to friction between the tires and the road, and in the chain and gears.

Mechanical energy  ---> Sound energy:
Some energy is also converted into sound when the bicycle makes noise while moving.

Summary:
Chemical energy  -> Mechanical energy  ->  ( Kinetic energy + Heat energy + Sound energy )

Q2. The potential energy of a freely falling object decreases progressively. Does this violate the law of conservation of energy? Why?

No, it does not violate the law of conservation of energy.

Explanation:

  • As the object falls, its potential energy decreases because its height decreases.
  • At the same time, its kinetic energy increases because its speed increases.
  • The total energy (potential energy + kinetic energy) of the object remains constant during the fall, ignoring air resistance.

So, energy is not lost. it is just converted from potential energy to kinetic energy, which obeys the law of conservation of energy.

Q3. A mass of 10 kg is at a point A on a table. It is moved to a point B. If the line joining A and B is horizontal, what is the work done on the object by the gravitational force? Explain your answer.

The work done by the gravitational force is zero.

Explanation:

Work done by gravity depends only on the vertical movement.
Here, the object moves horizontally from A to B. There is no change in height, so gravity does not do any work.

Since vertical displacement is zero,
Work done = m × g × height change = 0

So, the gravitational force does no work in this case.

Q4. Certain force acting on a 20 kg mass changes its velocity from 5 m/s to 2 m/s. Calculate the work done by the force.

To find the work done, we use the formula for change in kinetic energy:

Work done = ½ m (v₂² – v₁²)

Here:
m = 20 kg
v₁ = 5 m/s
v₂ = 2 m/s

Now,
Work done = ½ × 20 × (2² – 5²)
= 10 × (4 – 25)
= 10 × (–21)
= –210 J

So, the work done by the force is –210 joules.

Q5. A battery lights a bulb. Describe the energy changes involved in the process

When a battery lights a bulb, the following energy changes take place:

  • Chemical energy is stored in the battery.
  • When the circuit is completed, the battery converts its chemical energy into electrical energy.
  • The electrical energy flows through the bulb.
  • Inside the bulb, electrical energy is changed into light energy and heat energy.

So the energy change is:
Chemical energy   ------>  Electrical energy   --------->   Light energy  +  Heat energy.

Q6. An object is thrown at an angle to the ground. It moves in a curved path and falls back to the ground. The starting and ending points are at the same height. What is the work done by gravity on the object?

The work done by gravity is zero.

As work done by gravity:
W = m * g * (h_initial – h_final)

Since the object starts and ends at the same height:
h_initial = h_final

So,
W = m * g * (h_initial – h_initial) = 0

Therefore, the net work done by gravity is zero.

Q7. A lamp consumes 1000 J of electrical energy in 10 s. What is its power?

Power is calculated using the formula: Power = Work done ÷ Time taken.

Here, the work done (energy) = 1000 J and time = 10 s.
Power = 1000 ÷ 10 = 100 W

So, the power of the lamp is 100 watts.

Q8. Define 1 watt of power.

One watt of power is said to be produced when 1 joule of work is done in 1 second.

In simple words:
1 watt = 1 joule ÷ 1 second

Q9. What is power?

Power is the rate at which work is done. In simple words, it tells us how fast work is being done. The more quickly work is done, the greater the power.

The formula for power is:
Power = Work done ÷ Time taken

Q10. The kinetic energy of an object of mass m moving with a velocity of 5 m/s is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

We know that kinetic energy (KE) = ½ × mass × velocity².

When velocity is doubled:
New velocity = 2 × 5 = 10 m/s
New KE = ½ × m × (10)² = ½ × m × 100
Since original KE = 25 J, new KE = 4 × 25 = 100 J

When velocity is tripled:
New velocity = 3 × 5 = 15 m/s
New KE = ½ × m × (15)² = ½ × m × 225
New KE = 9 × 25 = 225 J

So, the kinetic energy will be 100 J when the velocity is doubled and 225 J when the velocity is tripled.

Q11. Write an expression for the kinetic energy of an object.

The kinetic energy of an object is given by the formula:
Kinetic Energy = ½ mv²

Here, m is the mass of the object and v is its velocity. This formula shows that the kinetic energy increases if the object is heavier or if it moves faster.

Q12. What is the kinetic energy of an object?

Kinetic energy is the energy an object has because it is moving. Any object that is in motion, whether fast or slow, carries some amount of kinetic energy. If the object moves faster or has more mass, its kinetic energy becomes greater. This energy is directly linked to the motion of the object.

Q13. A pair of bullocks exerts a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughing the length of the field?

Work done = Force × Distance
Work done = 140 N × 15 m
Work done = 2100 J

So, 2100 joules of work is done in ploughing the field.

Q14. Define 1 J of work.

One joule of work is said to be done when a force of  1 newton moves an object through a distance of  1 metrein the direction of the force.

In simple words, 1 J = 1 N × 1 m.

Q15. Write an expression for the work done when a force is acting on an object in the direction of its displacement.

When a force acts on an object and the object moves in the same direction, the work done is given by the simple expression:

Work done = Force × Displacement.

This means that the amount of work depends on how much force is applied and how far the object moves because of that force.

Q16. When do we say that work is done?

We say that work is done when a force applied on an object actually causes it to move. If the object shows some displacement in the direction of the applied force, then work is said to be done.

If the force is applied but there is no movement, then no work is done. In simple words, work is done only when force and motion both happen together.

Q17. A force of 7 N acts on an object. The displacement of the object is 8 m in the direction of the force. What is the work done by the force?

Work done = Force × Displacement
Work done = 7 N × 8 m = 56 J

So, the work done is 56 joules

Q18. How is the equal genetic contribution of male and female parents ensured in the progeny?

During reproduction, both parents produce gametes (sperm and egg) that contain half the number of chromosomes.
When the sperm and egg fuse during fertilisation, the child gets half the genes from the father and half from the mother.
This ensures equal genetic contribution from both parents in the progeny.

Q19. A study found that children with light-coloured eyes are likely to have parents with light-coloured eyes. On this basis, can we say anything about whether the light eye colour trait is dominant or recessive? Why or why not?

No, we cannot say whether light eye colour is dominant or recessive.
Children often resemble their parents, but this does not tell us which trait is stronger.
To know dominance or recessiveness, we need controlled crosses or more detailed genetic information, not just observation.

Q20. A Mendelian experiment consisted of breeding tall pea plants bearing violet flowers with short pea plants bearing white flowers. The progeny all bore violet flowers, but almost half of them were short. This suggests that the genetic make-up of the tall parent can be depicted as (a) TTWW (b) TTww (c) TtWW (d) TtWw

Short parent = ttww (short + white)
All progeny have violet flowers, so the tall parent must give a W to every child → therefore the tall parent must be WW.
Almost half of the progeny are short, which means the tall parent must be Tt (so it can give t to some children).

So the tall parent’s genotype = TtWW
Correct option: (c) TtWW

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