Questions Related to Science
Updated on November 6, 2025 | By Learnzy Academy
Q101. What is the atomicity of Argon?
The atomicity of Argon is 1.
Argon is a noble gas and exists as a single atom (monatomic) because it has a completely filled outermost electron shell, making it stable and unreactive.
Q102. What are polyatomic ions? Give two examples.
Polyatomic ions are ions that consist of two or more atoms bonded together covalently and carry a net positive or negative charge. These atoms act as a single charged unit in chemical reactions.
Examples:
- Ammonium ion – NH₄⁺
- Sulphate ion – SO₄²⁻
Q103. What is the number of electrons in Mg atom and Mg²⁺ ion?
The atomic number of magnesium (Mg) is 12.
In a neutral Mg atom, the number of electrons = number of protons = 12.
In a Mg²⁺ ion, the atom loses 2 electrons, so the number of electrons = 12 − 2 = 10.
Therefore:
Mg atom → 12 electrons
Mg²⁺ ion → 10 electrons
Q104. ‘Atoms of most elements are not able to exist independently.’ Name two atoms which exist as independent atoms.
The two atoms which can exist independently are Helium (He) and Argon (Ar).
These are noble gases and exist as single atoms because they have a completely filled outermost electron shell, making them stable and unreactive.
Q105. Name the element which is used as the reference for atomic mass.
The element used as the reference for atomic mass is Carbon.
The isotope Carbon-12 (C-12) is taken as the standard reference, and its atomic mass is defined as exactly 12 atomic mass units (amu)
Q106. Which organisation approves the names of elements all over the world ? Write the symbol of gold.
The organisation that approves the names of elements all over the world is the International Union of Pure and Applied Chemistry (IUPAC).
The symbol of gold is Au
Q107. Define law of constant proportion.
The Law of Constant Proportion states that a chemical compound always contains the same elements in the same fixed ratio by mass, regardless of its source or method of preparation.
Example:
Water (H₂O) always contains hydrogen and oxygen in the ratio of 1:8 by mass, whether it is obtained from a river, rain, or produced in a laboratory.
Q108. Define law of conservation of mass.
The Law of Conservation of Mass states that mass can neither be created nor destroyed in a chemical reaction.
According to this law, the total mass of the reactants is always equal to the total mass of the products.
Example:
When hydrogen reacts with oxygen to form water,
2H₂ + O₂ → 2H₂O
The total mass of hydrogen and oxygen before the reaction is equal to the mass of water formed after the reaction.
Q109. Name the scientist who laid the foundation of chemical sciences. How?
The scientist who laid the foundation of chemical sciences was Antoine Lavoisier.
He is known as the Father of Modern Chemistry because he:
- Established the Law of Conservation of Mass, which states that matter can neither be created nor destroyed in a chemical reaction.
- Gave a clear definition of elements and compounds.
- Helped develop a systematic naming system for chemical substances.
Q110. Calculate the molar mass of the following substances: (a) Ethyne, C₂H₂ (b) Sulphur molecule, S₈ (c) Phosphorus molecule, P₄ (Atomic mass of phosphorus = 31) (d) Hydrochloric acid, HCl (e) Nitric acid, HNO₃
(a) Ethyne (C₂H₂)
= (2 × 12) + (2 × 1)
= 24 + 2
= 26 g/mol
(b) Sulphur molecule (S₈)
= 8 × 32
= 256 g/mol
(c) Phosphorus molecule (P₄)
= 4 × 31
= 124 g/mol
(d) Hydrochloric acid (HCl)
= (1 × 1) + (1 × 35.5)
= 1 + 35.5
= 36.5 g/mol
(e) Nitric acid (HNO₃)
= (1 × 1) + (1 × 14) + (3 × 16)
= 1 + 14 + 48
= 63 g/mol
Q111. Give the names of the elements present in the following compounds: (a) Quick lime (b) Hydrogen bromide (c) Baking powder (d) Potassium sulphate
(a) Quick lime (CaO) ----> Calcium and Oxygen
(b) Hydrogen bromide (HBr) ----> Hydrogen and Bromine
(c) Baking powder (NaHCO₃) -----> Sodium, Hydrogen, Carbon, and Oxygen
(d) Potassium sulphate (K₂SO₄) ------> Potassium, Sulphur, and Oxygen
Q112. Write the chemical formulae of the following: (a) Magnesium chloride (b) Calcium oxide (c) Copper nitrate (d) Aluminium chloride (e) Calcium carbonate
(a) Magnesium chloride ----> MgCl₂
(b) Calcium oxide ----> CaO
(c) Copper nitrate -----> Cu(NO₃)₂
(d) Aluminium chloride ----> AlCl₃
(e) Calcium carbonate ------> CaCO₃
Q113. What are polyatomic ions? Give examples.
Polyatomic ions are ions that contain two or more atoms joined together by covalent bonds and carry a net positive or negative charge. These atoms act as a single charged unit during chemical reactions.
Examples:
- Ammonium ion (NH₄⁺)
- Hydroxide ion (OH⁻)
- Nitrate ion (NO₃⁻)
- Sulphate ion (SO₄²⁻)
- Carbonate ion (CO₃²⁻)
Thus, polyatomic ions are groups of atoms that behave as one charged particle.
Q114. When 3.0 g of carbon is burnt in 8.00 g of oxygen, 11.00 g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00 g of oxygen? Which law of chemical combination will govern your answer?
From the data:
3.0 g of carbon + 8.0 g of oxygen ----> 11.0 g of carbon dioxide
This means 3 g of carbon requires 8 g of oxygen to form 11 g of carbon dioxide.
Now, if 3 g of carbon is burnt in 50 g of oxygen, carbon is the limiting reactant because it can combine only with 8 g of oxygen. The remaining oxygen will be left unused.
So, the amount of carbon dioxide formed will still be 11 g.
Mass of carbon dioxide formed = 11.0 g
Law governing the reaction:
This is governed by the Law of Constant Proportion, which states that a chemical compound always contains the same elements in the same fixed ratio by mass.
Q115. A 0.24 g sample of a compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Total mass of the compound = 0.24 g
Mass of boron = 0.096 g
Mass of oxygen = 0.144 g
Percentage of boron = (0.096 / 0.24) × 100 = 40%
Percentage of oxygen = (0.144 / 0.24) × 100 = 60%
Therefore, the percentage composition of the compound is:
Boron = 40%
Oxygen = 60%
Q116. The volume of a 500 g sealed packet is 350 cm³. Will the packet float or sink in water if the density of water is 1 g/cm³? What will be the mass of the water displaced by this packet?
Density of the packet = Mass / Volume = 500 g / 350 cm³ = 1.43 g/cm³
Since the density of the packet (1.43 g/cm³) is greater than the density of water (1 g/cm³), the packet will sink in water.
Mass of water displaced = Volume of packet × Density of water
= 350 cm³ × 1 g/cm³
= 350 g
Final Answer:
The packet will sink in water, and the mass of water displaced is 350 g.
Q117. The volume of 50 g of a substance is 20 cm³. If the density of water is 1 g/cm³, will the substance float or sink?
Density of the substance = Mass / Volume = 50 g / 20 cm³ = 2.5 g/cm³
Since the density of the substance (2.5 g/cm³) is greater than the density of water (1 g/cm³), the substance will sink in water.
Q118. Why does a block of plastic released under water come up to the surface of water?
A block of plastic comes up to the surface of water because the buoyant force acting on it is greater than its weight. Since the density of plastic is less than the density of water, the upward buoyant force pushes it up until it reaches the surface.
Q119. In what direction does the buoyant force on an object immersed in a liquid act?
The buoyant force on an object immersed in a liquid acts vertically upward, that is, opposite to the direction of gravity.
Q120. A ball thrown up vertically returns to the thrower after 6 s. Find (a) the velocity with which it was thrown up, (b) the maximum height it reaches, and (c) its position after 4 s.
(a) Time to rise to top = half the total time = 6/2 = 3 s.
Initial velocity u = g × time = 10 × 3 = 30 m/s.
(b) Maximum height H = u² / (2g) = (30)² / (2 × 10) = 900 / 20 = 45 m.
(c) Position after t = 4 s (take upward as positive, origin at thrower):
y = ut − ½ g t² = 30×4 − ½×10×4² = 120 − 80 = 40 m above the thrower.
Final answers:
(a) 30 m/s upward
(b) 45 m
(c) 40 m above the thrower (after 4 s)