The capacity of a cylindrical tank is 6160 cm³. Its base diameter is 28 m. What is the depth of this tank?

Updated on May 31, 2025 | By Learnzy Admin

We are given:

Volume of the cylinder (V) = 6160 cm³
Diameter of the base = 28 m = 2800 cm  (1 m = 100 cm)
Then radius (r) = diameter ÷ 2 = 2800 ÷ 2 = 1400 cm

Step 1: - Use the formula for the volume of a cylinder
Volume (V) = π × r² × h
Where:
V = volume
r = radius
h = height (depth)

Substitute the known values:
6160 = π × (1400)² × h
6160 = π × 1,960,000 × h

Solve for h:
h = 6160 ÷ (π × 1,960,000)
=>  h = 6160 ÷ (3.1416 × 1,960,000)
=>  h = 6160 ÷ 6,157,536
=>  h = 0.001 cm

Hence depth of the tank is 0.001 cm

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