If one zero of the polynomial (a² + 9)x² + 13x + 6a is the reciprocal of the other, find the value of a.
If one zero of the polynomial (a² + 9)x² + 13x + 6a is the reciprocal of the other, find the value of a.
Step 1: Use the relationship between the roots
Let the roots be α and β, and it's given that α = 1/β.
Product of roots of a quadratic: αβ = c/a = 6a / (a² + 9)
Since α = 1/β, we get: αβ = 1
Step 2: Solve the equation
6a / (a² + 9) = 1
⇒ 6a = a² + 9
⇒ a² - 6a + 9 = 0
Step 3: Factor the quadratic
a² - 6a + 9 = (a - 3)² = 0
Therefore, a = 3
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