Real numbers are the set of numbers that include both rational and irrational numbers. They can be plotted on a number line, which makes them easy to understand and visualize.
Real Numbers carries steady weightage in Class 10th exams. Practising its MCQs and important questions is one of the fastest ways to secure marks from this chapter.
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32 students in section A
36 students in section B
This means we are looking for the Least Common Multiple (LCM) of 32 and 36.
32 = 2⁵
36 = 2² × 3²
LCM takes the highest powers of all prime factors involved:
LCM = 2⁵ × 3² = 32 × 9 = 288
Hence answer is 288 books
To solve this, we need to find the least number which, when divided by 6, 15, and 18, leaves a remainder of 5 in each case.
Step 1: Find LCM of 6, 15, and 18
Take the highest powers of all primes:
LCM =21 × 32 × 51 = 90
So, the least number is: 90 + 5 = 95
Prime factorization:
8 = 2³
15 = 3 × 5
21 = 3 × 7
LCM = 2³ × 3 × 5 × 7 = 8 × 3 × 5 × 7 = 840
So, any number divisible by 8, 15, and 21 must be a multiple of 840.
Divide 110000 by 840:
110000 ÷ 840 ≈ 130.95
Now check nearby multiples:
130 × 840 = 109200
131 × 840 = 110040
132 × 840 = 110880
Among these, 110040 is the nearest to 110000 and is greater than 100000.
Hence answer is 110040
To solve this problem, we need to find the greatest common divisor (GCD) of the three given quantities: 403 litres, 434 litres, and 465 litres.
The GCD will be the maximum capacity of a container that can measure all three amounts an exact number of times.
Find the GCD of 403, 434, and 465
Step 1: GCD of 403 and 434
Use the Euclidean algorithm:
434 ÷ 403 = 1 remainder 31
403 ÷ 31 = 13 remainder 0
So, GCD(403, 434) = 31
Step2: Now, GCD 31 and 465
465 ÷ 31 = 15 remainder 0
So, GCD(31, 465) = 31
Hence the maximum capacity of the container that can measure all three diesel quantities exactly is 31 litres.
It is given -
Now we use the identity
HCF x LCM = Product of both Number
2 x 60 = 6 x a
=> a = 20
Final Answer: 20
7× 11 × 13 + 13 can be wriiten as 13 (7× 11 + 1).
=> 13 x (77 + 1)
=> 13 x 78
=> 13 x 2 x 39
Clearly, this has more than 2 factors.
So, 7× 11 × 13 + 13 is a composite number.
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