Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.

Updated on May 31, 2025 | By Learnzy Admin

To solve this, we need to find the least number which, when divided by 6, 15, and 18, leaves a remainder of 5 in each case.

Step 1:  Find LCM of 6, 15, and 18

  • 6     =   2  ×  3
  • 15   =  3   ×  5
  • 18   =  2   ×   32

Take the highest powers of all primes:
LCM     =21  ×  32  ×   51   =   90

So, the least number is: 90 + 5 = 95

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