Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
To solve this, we need to find the least number which, when divided by 6, 15, and 18, leaves a remainder of 5 in each case.
Step 1: Find LCM of 6, 15, and 18
- 6 = 2 × 3
- 15 = 3 × 5
- 18 = 2 × 32
Take the highest powers of all primes:
LCM =21 × 32 × 51 = 90
So, the least number is: 90 + 5 = 95
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