Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.
Updated on May 31, 2025 | By Learnzy Admin
To solve this problem, we need to find the greatest common divisor (GCD) of the three given quantities: 403 litres, 434 litres, and 465 litres.
The GCD will be the maximum capacity of a container that can measure all three amounts an exact number of times.
Find the GCD of 403, 434, and 465
Step 1: GCD of 403 and 434
Use the Euclidean algorithm:
434 ÷ 403 = 1 remainder 31
403 ÷ 31 = 13 remainder 0
So, GCD(403, 434) = 31
Step2: Now, GCD 31 and 465
465 ÷ 31 = 15 remainder 0
So, GCD(31, 465) = 31
Hence the maximum capacity of the container that can measure all three diesel quantities exactly is 31 litres.
Click here to download practice questions on
Real Numbers
More Questions on Real Numbers
- In a school there are two sections – section A and section B of class X. There are 32 students in section A and 36 students in section B. Determine the minimum number of books required for their class library so that they can be distributed equally among students of section A or section B.
- Determine the number nearest 110000 but greater than 100000 which is exactly divisible by each of 8, 15 and 21.
- If HCF(6, a) = 2 and LCM(6, a) = 60 then find the value of a.
- Find the least number which when divided by 6, 15 and 18 leave remainder 5 in each case.
- Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.
- Prove that 7×11×13 +13 is a composite number.
- If the HCF of two numbers is 16 and their product is 3072, find their LCM.
- Find the smallest number that when divided by 12, 16, and 24 leaves a remainder of 4 in each case.
- Find the smallest number that is divisible by 6, 10, and 15, and leaves a remainder of 5 in each case.
- The product of HCF and LCM of 60,84 and 108 is
- The LCM of 60, 84 and 108 is
- If the product of two positive integers is equal to the product of their HCF and LCM is true then, the HCF (32 , 36) is