Verified Solution Mathematics Quadratic Equations

For what values of p does the quadratic equation x² + px + 1 = 0 have real roots?

7 views 2 helpful Updated Jul 14, 2026
Solution ✔ Verified
  • A-2 < p < 2
  • Bp > 2
  • Cp < -2
  • Dp <= -2 or p >= 2
Explanation

For real roots, the discriminant D must be greater than or equal to 0. D = p² - 4(1)(1) = p² - 4. So, p² - 4 >= 0 => p² >= 4. This implies p <= -2 or p >= 2.

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