Verified Solution Physics Units and Measurements

The dimensions of electric potential (V) are [M L² T^-3 A^-1]. What are the dimensions of resistance (R) if V = IR, where I is current (Ampere)?

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Solution ✔ Verified
  • AM L² T^-3 A^-2
  • BM L T^-3 A^-2
  • CM L² T^-2 A^-2
  • DM L² T^-3 A^-1
Explanation

From V = IR, Resistance R = V/I. Dimensions of V = [M L² T^-3 A^-1]. Dimensions of I = [A]. Dimensions of R = [M L² T^-3 A^-1] / [A] = [M L² T^-3 A^-2].

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