Verified Solution Mathematics Polynomials

If alpha and beta are the zeros of the polynomial f(x) = ax² + bx + c, then (1/alpha + 1/beta)² is equal to:

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Solution ✔ Verified
  • A(b² - 4ac) / c²
  • Bb² / c²
  • C(b² + 4ac) / c²
  • Db² / a²
Explanation

We know 1/alpha + 1/beta = (alpha + beta) / (alpha * beta).

Since alpha + beta = -b/a and alpha * beta = c/a, then (1/alpha + 1/beta) = (-b/a) / (c/a) = -b/c.

Therefore, (1/alpha + 1/beta)² = (-b/c)² = b²/c².

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