Verified Solution Mathematics Polynomials

If alpha and beta are the zeros of the quadratic polynomial P(x) = x² - 6x + 4, find a quadratic polynomial whose zeros are 3alpha and 3beta.

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Solution ✔ Verified
  • Ax² - 18x + 36
  • Bx² - 18x + 12
  • Cx² - 6x + 12
  • Dx² - 18x + 4
Explanation

For P(x), alpha + beta = 6 and alpha * beta = 4. For the new polynomial, the sum of zeros is 3alpha + 3beta = 3(alpha + beta) = 3(6) = 18. The product of zeros is (3alpha)(3beta) = 9(alpha * beta) = 9(4) = 36. The new polynomial is x² - (sum)x + (product) = x² - 18x + 36.

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