Verified Solution Physics Units and Measurements

Modified Question: A physical quantity has dimensions [M^x L^y T^z]. If this quantity is proportional to mass, the square of velocity and inversely proportional to length, what is the relation between x, y, z?

6 views 2 helpful Updated Jul 13, 2026
Solution ✔ Verified
  • Ax=1, y=0, z=-2
  • Bx=1, y=1, z=-2
  • Cx=0, y=1, z=-2
  • Dx=1, y=-1, z=-2
Explanation

Let the quantity be P. P ∝ m * v² / L. Dimensions of m = [M], v = [L T^-1], L = [L]. So, P ∝ [M] * ([L T^-1])² / [L] = [M] * [L² T^-2] / [L] = [M L T^-2]. Comparing with [M^x L^y T^z], we get x=1, y=1, z=-2. This quantity represents Force.

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