Verified Solution Science Exploring Forces

A rectangular block of wood has dimensions 20 cm x 10 cm x 5 cm and a mass of 1 kg. If it is placed on a table such that its largest face (20 cm x 10 cm) is in contact with the table, and then re-placed such that its smallest face (10 cm x 5 cm) is in contact, what is the ratio of the pressure exerted in the first case to the pressure exerted in the second case? (Assume g = 10 m/s²)

8 views 2 helpful Updated Jun 30, 2026
Solution ✔ Verified
  • A1:4
  • B4:1
  • C1:2
  • D2:1
Explanation

The force exerted is the weight of the block, which is constant (Force = mass x g = 1 kg x 10 m/s² = 10 N). Pressure = Force / Area. Area1 (largest face) = 20 cm x 10 cm = 200 cm². Area2 (smallest face) = 10 cm x 5 cm = 50 cm². Since pressure is inversely proportional to area (for constant force), P1:P2 = Area2:Area1 = 50 cm² : 200 cm² = 1:4.

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