Verified Solution Science The Human Eye and the Colourful World

A person needs a lens of power -5.5 D for correcting his distant vision. For correcting his near vision, he needs a lens of power +1.5 D. Calculate the focal length of the lens required for correcting (i) distant vision and (ii) near vision.

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Answer

For distant vision (myopia): Power (P1) = -5.5 D. Focal length (f1) = 1/P1 = 1/(-5.5) m ≈ -0.1818 m or -18.18 cm. The negative sign indicates a concave lens.

For near vision (hypermetropia/presbyopia component): Power (P2) = +1.5 D. Focal length (f2) = 1/P2 = 1/(+1.5) m ≈ +0.6667 m or +66.67 cm. The positive sign indicates a convex lens.

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