Consider the equation y = A sin(kx - omega t), where y is displacement, A is amplitude, x is distance, t is time. Which of the following statements is dimensionally incorrect?

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Solution ✔ Verified
  • AThe dimension of (k * x) is [M⁰ L⁰ T⁰].
  • BThe dimension of (omega * t) is [M⁰ L⁰ T⁰].
  • CThe dimension of (omega / k) is [L T^-1].
  • DThe dimension of (A * k) is [T^-1].
Explanation

For y = A sin(kx - omega t) to be dimensionally correct, the arguments of the sine function (kx and omega t) must be dimensionless. So, [k] = [L^-1] and [omega] = [T^-1]. Thus, the dimension of (omega / k) = [T^-1] / [L^-1] = [L T^-1], which is speed (correct). The dimension of (A * k) = [L] * [L^-1] = [M⁰ L⁰ T⁰], which is dimensionless, not [T^-1].

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