In the equation F = Ax + Bx², where F is force and x is distance, the dimensions of A and B are respectively:

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Appears in NEET UG
Solution ✔ Verified
  • A[MLT^-2], [MLT^-1]
  • B[MLT^-3], [MLT^-2]
  • C[ML⁰T^-2], [ML^-1T^-2]
  • D[ML^-1T^-2], [ML^-2T^-2]
Explanation

By homogeneity, [Ax] = [F] and [Bx²] = [F]. Dimensions of Force [F] = [MLT^-2] and distance [x] = [L]. For [A]: [A][L] = [MLT^-2] => [A] = [MLT^-2]/[L] = [MT^-2] = [ML⁰T^-2]. For [B]: [B][L²] = [MLT^-2] => [B] = [MLT^-2]/[L²] = [ML^-1T^-2].

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