A student measures the time period of 100 oscillations of a simple pendulum with a stopwatch having a least count of 1 s. The total time recorded is 200 s. The maximum possible percentage error in the measurement of the time period is:

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Appears in NEET UG
Solution ✔ Verified
  • A0.5%
  • B1%
  • C2%
  • D0.25%
Explanation

The absolute error in total time measurement (dt) is equal to the least count, i.e., 1 s. The measured total time (t) is 200 s. The percentage error in total time = (dt/t)*100 = (1/200)*100 = 0.5%. The time period (T) = t/N, where N is the number of oscillations. Since N is a pure number (100), the percentage error in T is the same as the percentage error in t. So, the maximum percentage error in the time period is 0.5%.

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