In the equation, P = P0 exp(-alpha t²), where P is pressure, t is time, and P0 is initial pressure. The dimensions of alpha are:

3 views 1 helpful Updated Jul 27, 2026
Appears in NEET UG
Solution ✔ Verified
  • A[M⁰ L⁰ T⁰]
  • B[T^-1]
  • C[T^-2]
  • D[LT^-2]
Explanation

For an exponential function exp(X), the exponent X must be dimensionless. So, [alpha t²] = [M⁰ L⁰ T⁰]. Therefore, [alpha][T²] = [M⁰ L⁰ T⁰]. This implies [alpha] = [T^-2].

Was this solution helpful?
1
Practice MCQs on Units & Dimensions — test yourself with instant answers. Start Practising