I will double-check each derivation before writing the question.The time period (T) of oscillations of a simple pendulum is measured as T = 2.00 s, and the length (L) of the pendulum is 1.00 m. The maximum percentage error in the measurement of T is 1% and in L is 2%. The acceleration due to gravity (g) is given by g = (4π² L) / T². What is the maximum percentage error in the measurement of g?

5 views 1 helpful Updated Jul 27, 2026
Appears in NEET UG
Solution ✔ Verified
  • A3%
  • B4%
  • C5%
  • D6%
Explanation

The formula for g is g = (4π² L) / T². The percentage error in g is given by (% error in L) + 2 * (% error in T). So, 2% + 2*(1%) = 4%.

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