A physical quantity X is given by X = (Fv²)/(WL²), where F is force, v is velocity, W is work, and L is length. The dimensions of X are:

6 views 1 helpful Updated Jul 27, 2026
Appears in NEET UG
Solution ✔ Verified
  • A[M L^-2 T^-2]
  • B[M^-1 L T^-2]
  • C[M⁰ L^-1 T^-2]
  • D[M L^-1 T^-1]
Explanation

Dimensions of F = [M L T^-2]. Dimensions of v = [L T^-1], so [v²] = [L² T^-2]. Dimensions of W = [M L² T^-2]. Dimensions of L = [L], so [L²] = [L²]. Therefore, [X] = ([M L T^-2] * [L² T^-2]) / ([M L² T^-2] * [L²]) = [M L³ T^-4] / [M L⁴ T^-2] = [M⁰ L^-1 T^-2].

Was this solution helpful?
1
Practice MCQs on Units & Dimensions — test yourself with instant answers. Start Practising