If the speed of light (c), acceleration due to gravity (g), and pressure (P) are taken as fundamental units, then the dimensions of a quantity having the same dimensions as the unit of length would be:

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Appears in NEET UG
Solution ✔ Verified
  • A[c² g^-1 P^-1]
  • B[c² g P^-1]
  • C[c⁰ g P^-1]
  • D[c² g^-1 P⁰]
Explanation

We want to find [L] in terms of [c], [g], [P]. Let [L] = [c]^x [g]^y [P]^z. Standard dimensions are [c] = [LT^-1], [g] = [LT^-2], [P] = [ML^-1T^-2]. Comparing powers of M, L, T: M: 0 = z => z=0. L: 1 = x+y-z => 1 = x+y. T: 0 = -x-2y-2z => 0 = -x-2y => x = -2y. Substituting x into L equation: 1 = -2y+y => 1 = -y => y=-1. Then x = -2(-1) = 2. So, [L] = [c² g^-1 P⁰].

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