The dimensions of the coefficient of thermal conductivity (k) are (from Q = -k A dT/dx):

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Appears in NEET UG
Solution ✔ Verified
  • A[M L T^-3 K^-1]
  • B[M L² T^-3 K^-1]
  • C[M L^-1 T^-3 K^-1]
  • D[M L T^-2 K^-1]
Explanation

Q is heat energy flowing per unit time (Power), so [Q] = [M L² T^-3]. A is area ([L²]). dT is temperature difference ([K]). dx is thickness ([L]). So [k] = [Q] / ([A] * [dT/dx]) = [M L² T^-3] / ([L²] * ([K]/[L])) = [M L^(2-1) T^-3 K^-1] = [M L T^-3 K^-1].

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