If speed (v), acceleration (a), and force (F) are chosen as fundamental units, the dimension of Young's modulus will be:

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Appears in NEET UG
Solution ✔ Verified
  • A[F a^-2 v²]
  • B[F a² v^-4]
  • C[F a v^-2]
  • D[F a^-1 v²]
Explanation

Young's modulus (Y) has dimensions of Stress, [M L^-1 T^-2]. We need to express M, L, T in terms of F, a, v. From [v] = [L T^-1] and [a] = [L T^-2], we derive [T] = [v/a] and [L] = [v²/a]. From [F] = [M L T^-2], we get [M] = [F] / ([L T^-2]) = [F] / ([v²/a] * [a²/v²]) = [F a^-1]. Substituting these into [Y] = [M L^-1 T^-2] gives [Y] = [F a^-1] * ([v² a^-1])^-1 * ([v a^-1])^-2 = [F a^-1] * [v^-2 a¹] * [v^-2 a²] = [F a² v^-4].

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