A student measures the diameter of a wire using a screw gauge. The reading on the main scale is 2 mm, and the 45th division on the circular scale coincides with the main scale line. The least count of the screw gauge is 0.01 mm. The diameter of the wire is:

4 views 1 helpful Updated Jul 27, 2026
Appears in NEET UG
Solution ✔ Verified
  • A2.45 mm
  • B2.045 mm
  • C2.450 mm
  • D2.405 mm
Explanation

Reading = Main Scale Reading (MSR) + (Circular Scale Reading (CSR) * Least Count (LC)). MSR = 2 mm. CSR = 45. LC = 0.01 mm. Reading = 2 mm + (45 * 0.01 mm) = 2 mm + 0.45 mm = 2.45 mm.

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