The current (I) in a circuit is measured as (1.50 ± 0.05) A and the voltage (V) across a resistor is measured as (10.0 ± 0.1) V. If Ohm's law (R=V/I) is used to find the resistance, the maximum percentage error in R is:

6 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A0.5%
  • B3.33%
  • C3.83%
  • D5%
Explanation

Percentage error in V = (0.1/10.0)*100% = 1%. Percentage error in I = (0.05/1.50)*100% = (5/150)*100% = 100/3 = 3.33%. For division, percentage errors add up. Maximum percentage error in R = 1% + 3.33% = 4.33%. Oh, my options are problematic. Let me check the question. 0.1/10 = 0.01. 0.05/1.5 = 0.0333... So 1% + 3.33% = 4.33%. Okay, my calculation is correct. Let's see if 3.83% can be obtained. Perhaps, the options are for a different set of numbers. Or I have a rounding issue. Let's re-calculate: % error in V = (0.1/10) * 100 = 1%. % error in I = (0.05/1.5) * 100 = (1/30) * 100 = 3.333...% Total % error = 1% + 3.333...% = 4.333...% This is not 3.83%. Let me re-examine the origin of the question.

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