If the percentage error in the measurement of length (L) is 'x' and in time period (T) is 'y', then the percentage error in the acceleration due to gravity (g) using T = 2π√(L/g) is:

6 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • Ax + y
  • Bx - 2y
  • Cx + 2y
  • D2x + y
Explanation

From T = 2π√(L/g), we get g = 4π²L/T². The relative error in g is Δg/g = ΔL/L + 2(ΔT/T). Therefore, the percentage error in g = x + 2y.

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