A physical quantity X is calculated using the formula X = (A+B)/C. If A = (10 ± 1), B = (20 ± 2), and C = (5 ± 0.5), what is the absolute error in X?

8 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A0.3
  • B0.6
  • C0.9
  • D1.2
Explanation

First, calculate A+B = 10 + 20 = 30. Absolute error in (A+B) = ΔA + ΔB = 1 + 2 = 3. So, (A+B) = (30 ± 3). Now, X = (A+B)/C = 30/5 = 6. Relative error in X = Δ(A+B)/(A+B) + ΔC/C = 3/30 + 0.5/5 = 0.1 + 0.1 = 0.2. Absolute error in X = X * (ΔX/X) = 6 * 0.2 = 1.2. Wait, my answer is 1.2 but the previous answer was 0.9. Let me check the old question again. The result is 1.2. Let's make it an option.

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