In an experiment, the values of two physical quantities P and Q are measured as P = (3.0 ± 0.3) unit and Q = (2.0 ± 0.1) unit. If a quantity R is calculated using the formula R = 2P²Q, what is the value of R with its absolute error?

5 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A(36 ± 9.0) unit
  • B(36 ± 7.2) unit
  • C(36 ± 10.8) unit
  • D(36 ± 12.0) unit
Explanation

First, calculate R = 2 * P² * Q = 2 * (3.0)² * (2.0) = 2 * 9 * 2 = 36 unit. Next, calculate the relative error: ΔR/R = 2(ΔP/P) + ΔQ/Q. ΔP/P = 0.3/3.0 = 0.1. ΔQ/Q = 0.1/2.0 = 0.05. So, ΔR/R = 2*(0.1) + 0.05 = 0.2 + 0.05 = 0.25. Absolute error ΔR = R * (ΔR/R) = 36 * 0.25 = 9.0 unit. So, R = (36 ± 9.0) unit.

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