A resistor of resistance R = 6 Ω is connected to a battery with voltage V = 12 V. If the errors in resistance and voltage are ΔR = 0.3 Ω and ΔV = 0.6 V, respectively, what is the percentage error in the current (I)? (I = V/R)

7 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A5%
  • B10%
  • C7.5%
  • D12.5%
Explanation

The current I = V/R. The fractional error in I is dI/I = dV/V + dR/R. Percentage error in I = (dV/V + dR/R) × 100. Substituting the values: %I = (0.6/12 + 0.3/6) × 100 = (0.05 + 0.05) × 100 = 0.10 × 100 = 10%.

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