The formula for the frequency of a mass-spring system is f = (1/2π)√(k/m). If the percentage error in the measurement of mass (m) is 2% and the spring constant (k) is 3%, what is the maximum percentage error in the frequency (f)?

8 views 2 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A1.0%
  • B1.5%
  • C2.0%
  • D2.5%
Explanation

f = (1/2π)k^(1/2)m^(-1/2). The constant (1/2π) has no error. The relative error in f is Δf/f = ½(Δk/k) + ½(Δm/m). Percentage error = ½*(3%) + ½*(2%) = 1.5% + 1% = 2.5%.

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