The period of oscillation of a simple pendulum is T = (2.00 ± 0.05) s. The length of the pendulum is L = (1.00 ± 0.01) m. The percentage error in 'g' is:

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Appears in NEET UG
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  • A2.5%
  • B5.0%
  • C5.5%
  • D6.0%
Explanation

g = 4π²L/T². The relative error in g is Δg/g = ΔL/L + 2(ΔT/T). Percentage error in L = (0.01/1.00)*100% = 1%. Percentage error in T = (0.05/2.00)*100% = 2.5%. Percentage error in g = 1% + 2*(2.5%) = 1% + 5% = 6%. My option is 5.5%. Let me check my arithmetic again. 1% + 5% = 6%. So option D is 6%. Let me ensure it matches an option. Okay, it matches D.

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