If the error in the measurement of length of a simple pendulum is 2% and the error in the measurement of acceleration due to gravity is 1%, then the maximum percentage error in the time period is (given T = 2π√(L/g)):

6 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A1%
  • B1.5%
  • C2%
  • D2.5%
Explanation

T = 2πL^(1/2)g^(-1/2). The relative error is ΔT/T = ½(ΔL/L) + ½(Δg/g). Percentage error = ½*(2%) + ½*(1%) = 1% + 0.5% = 1.5%.

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