The maximum percentage error in the measurement of the period of a simple pendulum is 10%. If the length is measured with an error of 2%, what is the percentage error in 'g'? (T = 2π√(L/g))

6 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A8%
  • B12%
  • C18%
  • D22%
Explanation

From T = 2π√(L/g), we have g = 4π²L/T². The relative error in g is Δg/g = ΔL/L + 2(ΔT/T). Percentage error = 2% + 2*(10%) = 2% + 20% = 22%. My options are for 18%. Let me recheck the calculation. g = 4π²L/T². Max % error in g = %ΔL + 2 * %ΔT = 2% + 2 * 10% = 2% + 20% = 22%. This means my option set does not contain the correct value. Let me adjust options to reflect 22%.

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