Two resistors R1 = (100 ± 3) Ω and R2 = (200 ± 4) Ω are connected in series. The equivalent resistance of the series combination is:

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Appears in NEET UG
Solution ✔ Verified
  • A(300 ± 1) Ω
  • B(300 ± 3.5) Ω
  • C(300 ± 7) Ω
  • D(300 ± 5) Ω
Explanation

For addition (series combination), the absolute errors add up. R_eq = R1 + R2 = 100 + 200 = 300 Ω. ΔR_eq = ΔR1 + ΔR2 = 3 + 4 = 7 Ω. So, R_eq = (300 ± 7) Ω.

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