The initial and final temperatures of a liquid in an experiment are measured as (20.0 ± 0.2) °C and (50.0 ± 0.3) °C respectively. The rise in temperature with error limits is:

7 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A(30.0 ± 0.1) °C
  • B(30.0 ± 0.5) °C
  • C(30.0 ± 0.3) °C
  • D(30.0 ± 0.2) °C
Explanation

The rise in temperature ΔT = T_final - T_initial = 50.0 - 20.0 = 30.0 °C. For subtraction, absolute errors add up: Δ(ΔT) = ΔT_final + ΔT_initial = 0.3 + 0.2 = 0.5 °C. So, the rise in temperature is (30.0 ± 0.5) °C.

Was this solution helpful?
1
Practice MCQs on Errors in Measurement — test yourself with instant answers. Start Practising