The length and diameter of a cylindrical wire are measured with errors of 1% and 2% respectively. What is the maximum percentage error in its volume?

7 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A3%
  • B5%
  • C6%
  • D7%
Explanation

Volume of cylinder V = π(d/2)²L = (π/4)d²L. The constant (π/4) has no error. Relative error in volume ΔV/V = 2(Δd/d) + ΔL/L. Percentage error = 2*(2%) + 1% = 4% + 1% = 5%.

Was this solution helpful?
1
Practice MCQs on Errors in Measurement — test yourself with instant answers. Start Practising