A student uses a simple pendulum of length L and performs n measurements of the time period T. He reports an average time period T_avg and a random error ΔT. The least count of the instrument used to measure length is ΔL. Which expression represents the maximum fractional error in the determination of g? (g = 4π²L/T²)

8 views 3 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • AΔL/L + 2ΔT/T_avg
  • BΔL/L + ΔT/T_avg
  • CΔL/L - 2ΔT/T_avg
  • DΔL/L + (ΔT/T_avg)²
Explanation

For g = 4π²L/T², the fractional error is given by dg/g = dL/L + 2(dT/T). The maximum fractional error is obtained by adding the absolute values of the fractional errors. Here, dL corresponds to ΔL and dT corresponds to ΔT. So, the maximum fractional error in g is ΔL/L + 2ΔT/T_avg.

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