The resistance of a wire is given by R = ρL/A. If the percentage error in the measurement of length L is 1%, radius r is 2%, and resistivity ρ is 3%, what is the maximum percentage error in the resistance R? (Area A = πr²)

7 views 1 helpful Updated Jul 26, 2026
Appears in NEET UG
Solution ✔ Verified
  • A4%
  • B6%
  • C8%
  • D9%
Explanation

R = ρL/A = ρL/(πr²). The constant π has no error. The relative error is ΔR/R = Δρ/ρ + ΔL/L + 2(Δr/r). Percentage error = 3% + 1% + 2*(2%) = 3% + 1% + 4% = 8%.

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