The density of a sphere is (5.0 ± 0.2) g/cm³. Its volume is (10.0 ± 0.1) cm³. What is the mass of the sphere with its absolute error?

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Appears in NEET UG
Solution ✔ Verified
  • A(50 ± 0.5) g
  • B(50 ± 2.0) g
  • C(50 ± 2.5) g
  • D(50 ± 2.6) g
Explanation

Mass m = Density ρ * Volume V = 5.0 * 10.0 = 50.0 g. Relative error in mass Δm/m = Δρ/ρ + ΔV/V = (0.2/5.0) + (0.1/10.0) = 0.04 + 0.01 = 0.05. Absolute error Δm = m * (Δm/m) = 50.0 * 0.05 = 2.5 g. Wait, my answer is 2.5g. So option C. Let's make sure the options are correct. Ah, I made a mistake in the explanation. Δm/m = 0.04 + 0.01 = 0.05. So Δm = 50 * 0.05 = 2.5. So the answer should be C: (50 ± 2.5) g.

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